12345678910111213/*Strong Connected ComponentTarjan's algorithm算法描述:使用 dfn 紀錄 DFS 順序stack 紀錄點如果能夠走回較小的 dfn代表存在強連通分量於是退棧將強連通點都取出反覆操作便可求得所有強連通分量用相鄰矩陣複雜度為 O(V^2),若是相鄰列表則為 O(V+E)*/
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123456789101112131415161718192021222324252627282930313233graph G = ( V, E )create S as stackProcedure DFS( integer u )	Index = Index + 1	dfn [ u ] = low [ u ] = Index	push u into S	for each ( u, v ) in E		if v is not visited then			tarjan( v )		if u is in S then			low [ u ] = min ( low [ u ], low [ v ] )	end for	if dfn [ u ] is equal to low [ u ] then		do			tmp = top element in S			pop element in S		while tmp is not uEnd ProcedureProcedure tarjan()	for u = 1 to n		if u is not visited then			DFS( i )	end forEnd Procedure
        
          
        
      
    110928 銘傳「小社遊」
          故事是這樣的,我只是因為某O在銘傳才報銘傳的結果一群人根本ㄎ一笑,居然有另外三人衝來銘傳……為啥不報北大呀…..真是瘋了…
以下是「社課」成績:
fxxs9xx92: 7題破台 <( )>m8xxx6xxlin : 6題mxxx72xx4) : 6題tfxxxo : 4題axxs : 4題黑白 : 3題sdxx5x2xx0 : 3題pxxx71xxx8 : 3題